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  1. Spring Integration
  2. INT-2850

Even after using URL-expression instead of url in outboundGateway - my url picked from payload has %22 at the start and end

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    • Support
    • Status: Resolved
    • Minor
    • Resolution: Invalid
    • None
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    • Adapters
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    Description

      Even after using Url-expression instead of url in outboundGateway - my url picked from payload has %22 at the start and end and gives the error

      Caused by: java.lang.IllegalStateException: Could not create URI object: Illegal character in scheme name at index 0: %22http://some.host/someService?someParam=someValue%22

      [Payload=http://some.host/someService?someParam=someValue]

      Exception Details
      org.springframework.integration.MessageHandlingException: HTTP request execution failed for URI ["http://some.host/someService?someParam=someValue]

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            mark.fisher Mark Fisher
            dheerja.arora@accenture.com dheerja arora
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              Updated:
              Resolved: