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  1. Spring Integration
  2. INT-2850

Even after using URL-expression instead of url in outboundGateway - my url picked from payload has %22 at the start and end

    Details

    • Type: Support
    • Status: Resolved
    • Priority: Minor
    • Resolution: Invalid
    • Affects Version/s: None
    • Fix Version/s: None
    • Component/s: Adapters
    • Labels:
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      Description

      Even after using Url-expression instead of url in outboundGateway - my url picked from payload has %22 at the start and end and gives the error

      Caused by: java.lang.IllegalStateException: Could not create URI object: Illegal character in scheme name at index 0: %22http://some.host/someService?someParam=someValue%22

      [Payload=http://some.host/someService?someParam=someValue]

      Exception Details
      org.springframework.integration.MessageHandlingException: HTTP request execution failed for URI ["http://some.host/someService?someParam=someValue]

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            • Assignee:
              mark.fisher Mark Fisher
              Reporter:
              dheerja.arora@accenture.com dheerja arora
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              • Created:
                Updated:
                Resolved: